IT-Passports.com Oracleの1Z1-051問題集

1Z1-051認定試験に合格することは難しいようですね。試験を申し込みたいあなたは、いまどうやって試験に準備すべきなのかで悩んでいますか。そうだったら、下記のものを読んでください。いま1Z1-051試験に合格するショートカットを教えてあげますから。あなたを試験に一発合格させる素晴らしい1Z1-051試験に関連する参考書が登場しますよ。それはIT-Passports.comの1Z1-051問題集です。気楽に試験に合格したければ、はやく試しに来てください。

多くのOracleの1Z1-051認定試験を準備している受験生がいろいろな1Z1-051認証試験についてサービスを提供するサイトオンラインがみつけたがIT-Passports.comはIT業界トップの専門家が研究した参考材料で権威性が高く、品質の高い教育資料で、一回に参加する受験者も合格するのを確保いたします。

人生には様々な選択があります。選択は必ずしも絶対な幸福をもたらさないかもしれませんが、あなたに変化のチャンスを与えます。IT-Passports.comのOracleの1Z1-051試験トレーニング資料はIT職員としてのあなたがIT試験に受かる不可欠なトレーニング資料です。IT-Passports.comのOracleの1Z1-051試験トレーニング資料はカバー率が高くて、更新のスピードも速くて、完全なトレーニング資料ですから、IT-Passports.com を手に入れたら、全てのIT認証が恐くなくなります。

天帝様は公平ですから、人間としての一人一人は完璧ではないです。私のように、以前が努力しなかったので、今は無駄に悩んでいます。現在のIT領域で競争が激しくなっていることは皆は良く知っていますから、みんなはIT認証を通じて自分の価値を高めたいです。私もそう思いますが、IT認証は私にとって大変難しいです。でも、幸い私はインターネットでIT-Passports.comのOracleの1Z1-051試験トレーニング資料を見つけました。それを手に入れてから私は試験に合格する自信を持つようになります。IT-Passports.comのOracleの1Z1-051試験トレーニング資料のカバー率がとても高いですから、自分で勉強するよりずっと効率が高いです。あなたもIT業種の一人としたら、ためらわずにIT-Passports.comのOracleの1Z1-051試験トレーニング資料をショッピングカートに入れましょう。IT-Passports.comはきっとあなたが成功への良いアシスタントになります。

IT-Passports.comが提供したOracleの1Z1-051の試験トレーニング資料は受験生の皆さんの評判を得たのはもうずっと前のことになります。それはIT-Passports.comのOracleの1Z1-051の試験トレーニング資料は信頼できるもので、確実に受験生を助けて試験に合格するということを証明しました。IT-Passports.comが提供したOracleの1Z1-051の試験トレーニング資料はベストセラーになって、ずっとピアの皆をリードしています。IT-Passports.comは消費者の皆さんの許可を得て、評判が良いです。Oracleの1Z1-051の認証試験を受けたら、速くIT-Passports.comというサイトをクッリクしてください。あなたがほしいものを得ることができますから、ミスしないだけで後悔しないです。最も専門的な、最も注目を浴びるIT専門家になりたかったら、速くショッピングカートに入れましょう。

あなたは弊社の商品を買ったら一年間に無料でアップサービスが提供された認定試験に合格するまで利用しても喜んでいます。もしテストの内容が変われば、すぐにお客様に伝えます。弊社はあなた１００％合格率を保証いたします。

IT-Passports.comを選ぶかどうか状況があれば、弊社の無料なサンプルをダウンロードしてから、決めても大丈夫です。こうして、弊社の商品はどのくらいあなたの力になるのはよく分かっています。IT-Passports.comはOracle 1Z1-051認証試験を助けって通じての最良の選択で、１００％のOracle 1Z1-051認証試験合格率のはIT-Passports.com最高の保証でございます。君が選んだのはIT-Passports.com、成功を選択したのに等しいです。

試験番号：1Z1-051問題集
試験科目：Oracle 「Oracle Database: SQL Fundamentals I」
問題と解答：全254問

購入前にお試し,私たちの試験の質問と回答のいずれかの無料サンプルをダウンロード：http://www.it-passports.com/1Z1-051.html

NO.1 Which SQL statements would display the value 1890.55 as $1,890.55? (Choose three .)
A. SELECT TO_CHAR(1890.55,'$0G000D00')
FROM DUAL;
B. SELECT TO_CHAR(1890.55,'$9,999V99')
FROM DUAL;
C. SELECT TO_CHAR(1890.55,'$99,999D99')
FROM DUAL;
D. SELECT TO_CHAR(1890.55,'$99G999D00')
FROM DUAL;
E. SELECT TO_CHAR(1890.55,'$99G999D99')
FROM DUAL;
Answer: ADE

Oracle   1Z1-051練習問題   1Z1-051   1Z1-051過去問

NO.2 You need to produce a report where each customer's credit limit has been incremented by $1000. In
the output, t he customer's last name should have the heading Name and the incremented credit limit
should be labeled New Credit Limit. The column headings should have only the first letter of each word in
uppercase .
Which statement would accomplish this requirement?
A. SELECT cust_last_name Name, cust_credit_limit + 1000
"New Credit Limit"
FROM customers;
B. SELECT cust_last_name AS Name, cust_credit_limit + 1000
AS New Credit Limit
FROM customers;
C. SELECT cust_last_name AS "Name", cust_credit_limit + 1000
AS "New Credit Limit"
FROM customers;
D. SELECT INITCAP(cust_last_name) "Name", cust_credit_limit + 1000
INITCAP("NEW CREDIT LIMIT")
FROM customers;
Answer: C

Oracle認定証   1Z1-051参考書   1Z1-051   1Z1-051

NO.3 You need to extract details of those products in the SALES table where the PROD_ID column
contains the string '_D123'.
Which WHERE clause could be used in the SELECT statement to get the required output?
A. WHERE prod_id LIKE '%_D123%' ESCAPE '_'
B. WHERE prod_id LIKE '%\_D123%' ESCAPE '\'
C. WHERE prod_id LIKE '%_D123%' ESCAPE '%_'
D. WHERE prod_id LIKE '%\_D123%' ESCAPE '\_'
Answer: B

Oracle   1Z1-051   1Z1-051   1Z1-051   1Z1-051認証試験   1Z1-051問題集

NO.4 View the Exhibit and examine the structure of the CUSTOMERS table.
Which two tasks would require subqueries or joins to be executed in a single statement? (Choose two.)
A. listing of customers who do not have a credit limit and were born before 1980
B. finding the number of customers, in each city, whose marital status is 'married'
C. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
D. listing of those customers whose credit limit is the same as the credit limit of customers residing in the
city 'Tokyo'
E. finding the number of customers, in each city, whose credit limit is more than the average credit limit of
all the customers
Answer: DE

Oracle問題集   1Z1-051認定証   1Z1-051参考書   1Z1-051練習問題   1Z1-051   1Z1-051

NO.5 View the E xhibit and examine the data in the EMPLOYEES table.
You want to generate a report showing the total compensation paid to each employee to date.
You issue the following query:
SQL>SELECT ename ' joined on ' hiredate
', the total compensation paid is '
TO_CHAR(ROUND(ROUND(SYSDATE-hiredate)/365) * sal + comm)
"COMPENSATION UNTIL DATE"
FROM employees;
What is the outcome?
A. It generates an error because the alias is not valid.
B. It executes successfully and gives the correct output.
C. It executes successfully but does not give the correct output.
D. It generates an error because the usage of the ROUND function in the expression is not valid.
E. It generates an error because the concatenation operator can be used to combine only two items.
Answer: C

Oracle   1Z1-051   1Z1-051   1Z1-051   1Z1-051

NO.6 View the Exhibit and examine the structure of the PRODUCTS table.
You need to generate a report in the following format:
CATEGORIES
5MP Digital Photo Camera's category is Photo
Y Box's category is Electronics
Envoy Ambassador's category is Hardware
Which two queries would give the required output? (Choose two.)
A. SELECT prod_name q'''s category is ' prod_category CATEGORIES
FROM products;
B. SELECT prod_name q'['s ]'category is ' prod_category CATEGORIES
FROM products;
C. SELECT prod_name q'\'s\' ' category is ' prod_category CATEGORIES
FROM products;
D. SELECT prod_name q'<'s >' 'category is ' prod_category CATEGORIES
FROM products;
Answer: CD

Oracle参考書   1Z1-051認証試験   1Z1-051参考書

NO.7 View the Exhibit; e xamine the structure of the PROMOTIONS table.
Each promotion has a duration of at least seven days .
Your manager has asked you to generate a report, which provides the weekly cost for each promotion
done to l date.
Which query would achieve the required result?
A. SELECT promo_name, promo_cost/promo_end_date-promo_begin_date/7
FROM promotions;
B. SELECT promo_name,(promo_cost/promo_end_date-promo_begin_date)/7
FROM promotions;
C. SELECT promo_name, promo_cost/(promo_end_date-promo_begin_date/7)
FROM promotions;
D. SELECT promo_name, promo_cost/((promo_end_date-promo_begin_date)/7)
FROM promotions;
Answer: D

Oracle認定証   1Z1-051   1Z1-051認定試験   1Z1-051

NO.8 View the Exhibit to examine the description for the SALES table.
Which views can have all DML operations performed on it? (Choose all that apply.)
A. CREATE VIEW v3
AS SELECT * FROM SALES
WHERE cust_id = 2034
WITH CHECK OPTION;
B. CREATE VIEW v1
AS SELECT * FROM SALES
WHERE time_id <= SYSDATE - 2*365
WITH CHECK OPTION;
C. CREATE VIEW v2
AS SELECT prod_id, cust_id, time_id FROM SALES
WHERE time_id <= SYSDATE - 2*365
WITH CHECK OPTION;
D. CREATE VIEW v4
AS SELECT prod_id, cust_id, SUM(quantity_sold) FROM SALES
WHERE time_id <= SYSDATE - 2*365
GROUP BY prod_id, cust_id
WITH CHECK OPTION;
Answer: AB

Oracle問題集   1Z1-051練習問題   1Z1-051問題集

NO.9 Examine the structure of the PROMOTIONS table:
name Null Type
PROMO_ID NOT NULL NUMBER(6)
PROMO_NAME NOT NULL VARCHAR2(30)
PROMO_CATEGORY NOT NULL VARCHAR2(30)
PROMO_COST NOT NULL NUMBER(10,2)
The management wants to see a report of unique promotion costs in each promotion category.
Which query would achieve the required result?
A. SELECT DISTINCT promo_cost, promo_category FROM promotions;
B. SELECT promo_category, DISTINCT promo_cost FROM promotions;
C. SELECT DISTINCT promo_cost, DISTINCT promo_category FROM promotions;
D. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;
Answer: D

Oracle参考書   1Z1-051認定資格   1Z1-051   1Z1-051   1Z1-051   1Z1-051

NO.10 View the Exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS, and TIMES
tables.
The PROD_ID column is the foreign key in the SALES table, which references the PRODUCTS table.
Similarly, the CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the
CUSTOMERS and TIMES tables, respectively.
Evaluate the following CREATE TABLE command:
CREATE TABLE new_sales(prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true regarding the above command?
A. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the
column definition.
B. The NEW_SALES table would get created and all the NOT NULL constraints defined on the specified
columns would be passed to the new table.
C. The NEW_SALES table would not get created because the column names in the CREATE TABLE
command and the SELECT clause do not match.
D. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the
specified columns would be passed to the new table.
Answer: B

Oracle認定試験   1Z1-051   1Z1-051   1Z1-051過去問   1Z1-051認定証

NO.11 Evaluate the following query:
SQL> SELECT promo_name q'{'s start date was }' promo_begin_date
AS "Promotion Launches"
FROM promotions;
What would be the outcome of the above query?
A. It produces an error because flower braces have been used.
B. It produces an error because the data types are not matching.
C. It executes successfully and introduces an 's at the end of each promo_name in the output.
D. It executes successfully and displays the literal " {'s start date was } " for each row in the output.
Answer: C

Oracle過去問   1Z1-051   1Z1-051認定試験

NO.12 Examine the structure of the SHIPMENTS table:
name Null Type
PO_ID NOT NULL NUMBER(3)
PO_DATE NOT NULL DATE
SHIPMENT_DATE NOT NULL DATE
SHIPMENT_MODE VARCHAR2(30)
SHIPMENT_COST NUMBER(8,2)
You want to generate a report that displays the PO_ID and the penalty amount to be paid if the
SHIPMENT_DATE is later than one month from the PO_DATE. The penalty is $20 per day.
Evaluate the following two queries:
SQL> SELECT po_id, CASE
WHEN MONTHS_BETWEEN (shipment_date,po_date)>1 THEN
TO_CHAR((shipment_date - po_date) * 20) ELSE 'No Penalty' END PENALTY
FROM shipments;
SQL>SELECT po_id, DECODE
(MONTHS_BETWEEN (po_date,shipment_date)>1,
TO_CHAR((shipment_date - po_date) * 20), 'No Penalty') PENALTY
FROM shipments;
Which statement is true regarding the above commands?
A. Both execute successfully and give correct results.
B. Only the first query executes successfully but gives a wrong result.
C. Only the first query executes successfully and gives the correct result.
D. Only the second query executes successfully but gives a wrong result.
E. Only the second query executes successfully and gives the correct result.
Answer: C

Oracle認定資格   1Z1-051参考書   1Z1-051   1Z1-051参考書   1Z1-051

NO.13 Which statement is true regarding the INTERSECT operator?
A. It ignores NULL values.
B. Reversing the order of the intersected tables alters the result.
C. The names of columns in all SELECT statements must be identical.
D. The number of columns and data types must be identical for all SELECT statements in the query.
Answer: D

Oracle参考書   1Z1-051   1Z1-051   1Z1-051認証試験   1Z1-051認証試験

NO.14 Using the CUSTOMERS table, you need to generate a report that shows 50% of each credit
amount in each income level. The report should NOT show any repeated credit amounts in each income
level.
Which query would give the required result?
A. SELECT cust_income_level, DISTINCT cust_credit_limit * 0.50
AS "50% Credit Limit"
FROM customers;
B. SELECT DISTINCT cust_income_level, DISTINCT cust_credit_limit * 0.50
AS "50% Credit Limit"
FROM customers;
C. SELECT DISTINCT cust_income_level ' ' cust_credit_limit * 0.50
AS "50% Credit Limit"
FROM customers;
D. SELECT cust_income_level ' ' cust_credit_limit * 0.50 AS "50% Credit Limit"
FROM customers;
Answer: C

Oracle過去問   1Z1-051   1Z1-051問題集   1Z1-051

NO.15 Which two statements are true regarding single row functions? (Choose two.)
A. They a ccept only a single argument.
B. They c an be nested only to two levels.
C. Arguments can only be column values or constants.
D. They a lways return a single result row for every row of a queried table.
E. They c an return a data type value different from the one that is referenced.
Answer: DE

Oracle   1Z1-051参考書   1Z1-051参考書   1Z1-051認定証   1Z1-051

NO.16 Which two statements are true regarding the USING and ON clauses in table joins? (Choose two.)
A. Both USING and ON clauses can be used for equijoins and nonequijoins.
B. A maximum of one pair of columns can be joined between two tables using the ON clause.
C. The ON clause can be used to join tables on columns that have different names but compatible data
types.
D. The WHERE clause can be used to apply additional conditions in SELECT statements containing the
ON or the USING clause.
Answer: CD

Oracle問題集   1Z1-051   1Z1-051練習問題

NO.17 Which three statements are true regarding the data types in Oracle Database 10g/11g? (Choose
three.)
A. Only one LONG column can be used per table.
B. A TIMESTAMP data type column stores only time values with fractional seconds.
C. The BLOB data type column is used to store binary data in an operating system file.
D. The minimum column width that can be specified for a VARCHAR2 data type column is one.
E. The value for a CHAR data type column is blank-padded to the maximum defined column width.
Answer: ADE

Oracle   1Z1-051   1Z1-051参考書

NO.18 View the Exhibit and examine the structure of the PRODUCTS table.
All products have a list price.
You issue the following command to display the total price of each product after a discount of 25% and a
tax of 15% are applied on it. Freight charges of $100 have to be applied to all the products.
SQL>SELECT prod_name, prod_list_price -(prod_list_price*(25/100))
+(prod_list_price -(prod_list_price*(25/100))*(15/100))+100
AS "TOTAL PRICE"
FROM products;
What would be the outcome if all the parenthese s are removed from the above statement?
A. It produces a syntax error.
B. The result remains unchanged.
C. The total price value would be lower than the correct value.
D. The total price value would be higher than the correct value.
Answer: B

Oracle参考書   1Z1-051   1Z1-051

NO.19 Evaluate the following query:
SELECT INTERVAL '300' MONTH,
INTERVAL '54-2' YEAR TO MONTH,
INTERVAL '11:12:10.1234567' HOUR TO SECOND
FROM dual;
What is the correct output of the above query?
A. +25-00 , +54-02, +00 11:12:10.123457
B. +00-300, +54-02, +00 11:12:10.123457
C. +25-00 , +00-650, +00 11:12:10.123457
D. +00-300 , +00-650, +00 11:12:10.123457
Answer: A

Oracle   1Z1-051   1Z1-051認定試験

NO.20 View the Exhibit and examine the data in the CUSTOMERS table.
Evaluate the following query:
SQL> SELECT cust_name AS "NAME", cust_credit_limit/2 AS MIDPOINT,MIDPOINT+100 AS "MAX
LOWER LIMIT"
FROM customers;
The above query produces an error on execution.
What is the reason for the error?
A. An alias cannot be used in an expression.
B. The a lias NAME should not be enclosed with in double quotation marks .
C. The MIDPOINT+100 expression gives an error because CUST_CREDIT_LIMIT contains NULL
values.
D. The a lias MIDPOINT should be enclosed with in double quotation marks for the
CUST_CREDIT_LIMIT/2 expression .
Answer: A

Oracle   1Z1-051認定証   1Z1-051   1Z1-051過去問

Oracleの1Z1-051認定試験を受験する気があるのですか。この試験を受けた身の回りの人がきっと多くいるでしょう。これは非常に大切な試験で、試験に合格して1Z1-051認証資格を取ると、あなたは多くのメリットを得られますから。では、他の人を頼んで試験に合格する対策を教えてもらったのですか。試験に準備する方法が色々ありますが、最も高効率なのは、きっと良いツールを利用することですね。ところで、あなたにとってどんなツールが良いと言えるのですか。もちろんIT-Passports.comの1Z1-051問題集です。